In ∆ABC if
TanA+TanB+TanC = k√3 find the value of k
kvnmurty:
perhaps some data is missing... with given data it not possible.
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ΔABC => m(∠A) + m(∠B) + m(∠C) = 180°. --- (1)
Using (1) we can obtain the relation:
Tan A + Tan B + Tan C = Tan A * Tan B * Tan C --- (2)
Given Tan A + Tan B + Tan C = k √3 --- (3)
There are two equations (2) and (3) given and we have three variables. So it is not possible to uniquely solve the problem.
But if we say that in all triangles ABC, (3) is satisfied, then:
Let A = B = C . So A = B = C = 60°
Substituting it in (3) :
we get 3 Tan 60° = k √3
3√3 = k √3
=> k = 3
Using (1) we can obtain the relation:
Tan A + Tan B + Tan C = Tan A * Tan B * Tan C --- (2)
Given Tan A + Tan B + Tan C = k √3 --- (3)
There are two equations (2) and (3) given and we have three variables. So it is not possible to uniquely solve the problem.
But if we say that in all triangles ABC, (3) is satisfied, then:
Let A = B = C . So A = B = C = 60°
Substituting it in (3) :
we get 3 Tan 60° = k √3
3√3 = k √3
=> k = 3
:-)
sir how will we solve if is it is not given = ,k√3 ?
what ?
nothing leave it
thanks for explanation
after 32 years rahima will be 5 times as old as he was 8 years ago how old is rahima today
pls solve the question do explain sir
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