Math, asked by ano0jbets3anver, 1 year ago

prove that cos squarex- cos square 6x=sin4x.sin8x

Answers

Answered by duragpalsingh
5
L.H.S. = cos^2 2x – cos^2 6x 

= (cos 2x + cos 6x) (cos 2x – 6x) 

= [2cos(2x+6x/2)cos(2x-6x/2)][-2sin(2x+6x/... 

= [2 cos 4x cos 2x] [–2 sin 4x (–sin 2x)] 

= (2 sin 4x cos 4x) (2 sin 2x cos 2x) 

= sin 8x sin 4x 

= R.H.S.

duragpalsingh: click on thanks link above
Ankit1234: ye bhi bhai se poocha hai
Ankit1234: tu jhoot bolna band nhi karega haina
Similar questions