Question

in ∆ABC is a isosceles triangle such that AB=AC , AD is perpendicular on BC then

(I) Prove that ∆ABD = ∆ ACD
(ii) <B = <C​

Answer 1

Step-by-step explanation:

Since AB = AC so

<B=< C

Angles opposite to equal sides are equal.

In ∆ABD and ∆ACD

AB= AC (given)

AD= AD (common)

<ADB= <ADC (90°)

so ∆ ABD~=∆ACD.

Hope you understand it........