In ▲ABC <A = 2x+15° , <B = 3x- 5° and < C= 4x+35° .Find each each angle of the triangle.
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angle A+Angle B+angle C=180°
2x+15+3x-5+4x+35=180°
9x+45=180
9x=180-45
9x=135
x=15
angle a=2×15+15
= 45°
angle b=3×15-5
=40°
angle c=4×15+35
=95°
2x+15+3x-5+4x+35=180°
9x+45=180
9x=180-45
9x=135
x=15
angle a=2×15+15
= 45°
angle b=3×15-5
=40°
angle c=4×15+35
=95°
Kshitijydv:
thanks for making my answer as a brainlist
Answered by
0
Hii------------
(2x+15°) +( 3x-5°)+( 4x+35°)= 180°
9x +45°=180°
9x =180- 45
x=135°/9=15°
hence angles are:
(2x+15)=2×15 ×15=45°
(3x-5) = 3 ×15-5= 40°
(4x +35)= 4×15 +35 =95°
HOPE IT HELPED ☺
(2x+15°) +( 3x-5°)+( 4x+35°)= 180°
9x +45°=180°
9x =180- 45
x=135°/9=15°
hence angles are:
(2x+15)=2×15 ×15=45°
(3x-5) = 3 ×15-5= 40°
(4x +35)= 4×15 +35 =95°
HOPE IT HELPED ☺
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