Question

in ∆ABC <A= 80°,<B=45° find c?​

Answer 1

Answer:

<A+<B+<C=180

80+45+<C=180

<C=180-125

<C=55°

Step-by-step explanation:

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Answer 2

Answer:

Answer = <c=55°

<A=80°

<B=45°

<C =?

<A+<B+<C = 180°(angles sum property in triangle)

80°+45°+<C=180°

125°+<C=180°

<C=180°-125°

<C=55°