In ∆ABC, <A=<C=45°,<B is 90° AC= 16√2cm , find AB=?
Answers
Answered by
0
Answer:
sin 45° = AC / AB
1 / √2 = 16√2 / AB
Step-by-step explanation:
AB = 16√2 × √2
AB = 16 × 2
AB = 32
plz mark as brainliest
as perfect step by step explaination
Similar questions