In ΔABC, m∠A = 90. AD is a median. If AD = 6, AB = 10, then AC =(a) 8
(b)7.2
(C)16
(d)2√11
hukam0685:
from where you get AD ,in Triangle ABC
I guess AD is the perpendicular on the hypotenuse i.e. BC.
yes,you may be right
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In the attachment I have answered this problem.
Concept:
Pythagoras theorem:In a right angle triangle square on the hypotenuse is equal to sum of the squares on the other two sides
See the attachment for detailed solution
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