Question

In ΔABC, m∠B=90.angle (AB) = 20cm and angle (BC) =21cm. find the angle (AC) ​

Answer 1

Answer:

AC = 29 cm

Step-by-step explanation:

Using Pythagoras theorem,

AC^2 = AB^2 + BC^2

AC^2 = 400+441

AC = √841

AC = 29 cm

Answer 2

Given :- In ∆ABC , Angle B = 90° , AB = 20cm and BC = 21 cm

To find :- AC

Solution :- ∆ABC = 90° ... ( given )

Therefore , by Pythagoras theorem ;

( Hyp )^2 = ( Side 1 )^2 + ( Side 2 )^2

( AC )^2 = ( AB )^2 + ( BC )^2

( AC )^2 = ( 20 )^2 + ( 21 )^2

( AC )^2 = 400 + 441

( AC )^2 = 841

AC = √ 841

Therefore , AC = 29

Therefore , AC = 29cm .

Hope this answer helps you friend ♥️