In ΔABC, point M is the midpoint of side BC. If, AB²+AC²= 290 cm²,AM=8cm, find BC.
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therefore BM = 9 CM
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HOPE IT WILL HELP U
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HOPE IT WILL HELP U
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Given :
In ∆ABC , point M is the midpoint of
side BC .
AB² + AC² = 290 cm² ,
AM = 8 cm
BC= ?
****************************************
By Appolonius Theorem :
The sum of the Squares of two sides
of a triangle is equal to twice the
square on half the third side plus
twice the square on the median which
bisects the third side .
*********************************************
Here ,
AB² + AC² = 2( BM² + AM² )
=> 290 = 2( BM² + 8² )
=> 145 = BM² + 64
=> 145 - 64 = BM²
=> 81 = BM²
=> 9² = BM
=> 9 = BM
Now ,
BC = BM + MC
=> BC = BM + BM
[ Since , M is midpoint of BC ]
=> BC = 2BM
BC = 2 × 9
BC = 18
••••
In ∆ABC , point M is the midpoint of
side BC .
AB² + AC² = 290 cm² ,
AM = 8 cm
BC= ?
****************************************
By Appolonius Theorem :
The sum of the Squares of two sides
of a triangle is equal to twice the
square on half the third side plus
twice the square on the median which
bisects the third side .
*********************************************
Here ,
AB² + AC² = 2( BM² + AM² )
=> 290 = 2( BM² + 8² )
=> 145 = BM² + 64
=> 145 - 64 = BM²
=> 81 = BM²
=> 9² = BM
=> 9 = BM
Now ,
BC = BM + MC
=> BC = BM + BM
[ Since , M is midpoint of BC ]
=> BC = 2BM
BC = 2 × 9
BC = 18
••••
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