In ABC, PQ II BC AND BD=DC Prove that PE=EQ
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In Triangle ABC, PQ || BC and BD = DC.
We know that AD bisects PQ and PE = EQ
We also know that PE || BD and EQ II DC
But, it is given that BD = DC, therefore,
PE II EQ
(Because if two or more lines are parallel to the same line then they are parallel to each other)
Hence, PE II EQ.
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