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ΔABC is a right triangle in which ∠B is a right angle, AB = 1, AC = 2, and BC = .
cos C × sin A =
Answers
Answered by
8
Answer:
Bc=√3/2
Step-by-step explanation:
Cos C × Sin A =3/4
Answered by
14
Step-by-step explanation:
by using phthagoras theorem .
H^2 = P^2 +B^2
(2)^2 =(1)^2 +B^2
B^2 = (2)^2 - (1)^2
B^2 = 4-1
B^2 = 3
B = √3
cosC = B/H
cosC = √3/2
sinA = P / H
sinA = 1/2
cosC × sin A
√3/2 × 1/2
== √3/2
hence prove
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