Question

in ∆abc∆pqr are midpoint pr=5cm pq=3cm qr=4cm find perimeter of ∆abc​

Answer 1

Answer:

A/Q midpoint theorem

2PR= BC.

BC= 2×5= 10 cm.

Similarly

2PQ=AC.

AC= 2×3= 6cm.

Similarly

2RQ=AB.

AB= 2× 4=8 cm.

so, perimeter of ∆ABC.

10+6+8= 24 cm. Ans.