Question

In(∆ABC)~∆QRP
ar(∆ABC)=9
ar(∆QRP)=4,and BC=15cm
then find PR.
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Answer 1

Answer:

in (/\ABC) ~(/\QPR)

ar (/\ABC)=9

ar (/\QPR)=4 AND BC=15CM

PR"2"=QR"2'+QP"2"

PR"2"=2"2"+2+"2"

PR"2"=4+4

PR"2"=8

PR=(8)"2"

PR=16

Answer 2

Length of the PR = 10cm

Step-by-step explanation:

since given that two triangles are similar.

AB/QR = BC\PR = AC\PQ

By known theorem " Ratios of the areas of two similar triangles is equal to the ratios of the squares of their corresponding sides".

(area of ∆ABC)/(area of ∆ QRP) = (BC²/PR²)

9/4 = 15²/PR²

9/4 = 225/PQ²

9PR² = 900

PR² = 100

PR = 10 cm.