Question

In ∆ ABC, Ray BD bisects Angle ABC
If A-D-C , A-E-B & Seg ED || Seg BC , Then Prove That : AB/BC = AE/EB​

Answer 1

Answer:

therefore AB/BC = AE/EB

Step-by-step explanation:

In ∆ ABC, ray BD bisects angle ABC.

If A-D-C, A-E-B and seg ED || side BC then prove that :

AB/BC = AE/EB

Proof:-

In ∆ABC,ray BD bisects angle ABC.

AB/BC = AD/DC ----(1) (by angle bisector theorem)

In ∆ABC,seg DE|| side BC

AE/EB = AD/DC -----(2) (midpoint theorem)

MARK ME AS BRAINLIESTED

Answer 2

This is answer....

I hope it's helps you.....

Follow me in brainly........