Question

In ∆ABC, right angled at B, AB = 24 cm and BC =7 cm. Determine
(i) sin A, cos A    (ii) sin C, cos C.

Answer 1

Explanation:

firstly use baudhyan or Pythagoras theorem

Answer 2

(i) Sin A = 7/25

Cos A = 24/25

(ii) Sin C = 24/25

Cos C = 7/25

Explanation:

Given:

Triangle ABC is right-angled at B.

AB = 24 cm

BC = 7 cm

AC = root of (AB^2 + BC^2) = root of (24^2 + 7^2) = root of (576 + 49) = root of 625 = 25 cm

(i) Sin A = side opposite to <A / hypotenuse = BC / AC = 7 / 25

Cos A = side adjacent to <A / hypotenuse = AB / AC = 24 / 25

(ii) Sin C = side opposite to <C / hypotenuse = AB / AC = 24 / 25

Cos C = side adjacent to <C / hypotenuse = BC / AC = 7 / 25