Question

. In ∆ ABC, right-angled at B, AB = 24 cm, BC = 7 cm. The value of tan C is: *
1 point
12/7
24/7
7/24
20/7
2. (Sin 30°+cos 60°)-(sin 60° + cos 30°) is equal to: *
1 point
0
1+2√3
1-√3
1+√3
3. The value of tan 60°/cot 30° is equal to: *
1 point
0
1
2
3
4. 1-cos^2(A) is equal to: *
1 point
sin^2(A)
tan^2(A)
1-sin^2(A)
sec^2(A)
5. Sin (90° – A) and cos A are: *
1 point
Different
Same
Not related
None of the above
6. If cos X = ⅔ then tan X is equal to: *
1 point
5/2
√(5/2)
√5/2
2/√5​

Answer 1

Answer:

1.24/7

2.1

3.1

4.sin^2 A.

5.i dont know.

6.root over 5/3.

Answer 2

Given :  ∆ ABC, right-angled at B, AB = 24 cm, BC = 7 cm

To Find : Value of Tan C

Solution:

in Right angle triangle

Tan (angle ) = Opposite side / Adjacent side   ( perpendicular / Base)

Tan C = AB / BC

=> Tan  C = 24/7

Correct option is 24/7

(Sin 30°+cos 60°)-(sin 60° + cos 30°)

= 1/2 + 1/2  - ( √3/2 + √3/2)

= 1  - √3

Correct option is 1-√3

tan 60°/cot 30°

Tan 60° = √3

cot 30° = √3

√3 /√3  = 1

=> tan 60°/cot 30° = 1

Correct option is 1

1 - cos²A = sin²A

Sin (90° – A) =  cos A

Hence

Sin (90° – A) and cos A are same

cos X = ⅔    B = 2 , H = 3

P = √H² - B²  = √3² - 2²   = √5

tan X = P/B   = √5 / 2

Correct option is   √5 / 2

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