Question

In ∆Abc right angled at B, AB=24cm, BC= 7m determine
(1) Sin A , cos A
(2) sin C , cos C

Answer 1

Solution

In Δ ABC, right-angled at B

using Pythagoras theorem

we have

AC² = AB² +BC²  

AC² = 24² + 7²

AC²576 + 49

AC²= 625

AC = √625

AC = 25

Now

 In a right angle triangle ABC where B=90°


(i) Sin A = BC/AC = 7/25
CosA = AB/AC = 24/25


(ii) Sin C = AB/AC = 24/25
Cos C = BC/AC =7/25

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Thanks☺️✌️

Answer 2

Answer:

ıllıllı ıllıllı

Step-by-step explanation:

In Δ ABC, right-angled at B ,using Pythagoras theorem we have

AC2 = AB2 +BC2  = 576 + 49 = 625

Or AC=25 ( taking positive value only)

Now

(i) In a right angle triangle ABC where B=90° ,

Sin A = BC/AC = 7/25

CosA = AB/AC = 24/25

(ii)

Sin C = AB/AC = 24/25

Cos C = BC/AC =7/25