In ∆ABC, the altitudes AD, BE and CF are equal. Prove that triangle ABC is an equilateral
triangle.
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see my all steps carefully and I hope this answer is definitely helpful for u :)
• In triangle ABE and triangle ACF
BE=CF (Given)
∠A=∠A (Common)
∠AEB=∠AFC=90°
By AAS congruent rule ABE ≅ ACF
AB=AC (CPCT)
Similarly
BCF ≅ ABD
AB=BC
AC=BC
AB=AC
AB = BC = AC..... Proved
©© The triangle is a equaliteral triangle ©©
Thanks :)
Hope this is helpful for u :)
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