In ΔABC, the bisector of ∠A intersects BC in D. Prove that BD=BC*AB/AB+AC and DC=BC*AC/AC+AB
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In the attachments I have answered this problem.
Concept:
Angle bisector theorem:
If the vertical angle of a triangle is bisected the bisector divides the base into two segments which have same the ratio as the order of other two sides.
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