Question

In ΔXYZ, the bisector of ∠Y intersects ZX in P.
(1) if XP : PZ = 4:5 and YZ = 6.5, find XY.
(2) if XY: YZ = 2:3 and XP = 3.8, find PZ and ZX.

Answer 1

(1) Given, XP : PZ = 4 : 5 and YZ =6.5

In ΔXYZ, the bisector of ∠Y intersects ZX in P.

then, according to angle bisector theorem,

XP/PZ = XY/YZ

4/5 =XY/6.5

XY = 5.2

(2)if XY: YZ = 2:3 and XP = 3.8, find PZ and ZX.

XP/PZ = XY/YZ

3.8/PZ = 2/3

PZ = 5.7

ZX = XP + PZ = 3.8 + 5.7 = 9.5
ZX = 9.5

Answer 2

Answer:

thank you for your answer abhi