In ΔABC, the measure of ㄥA is greater than the measure of ㄥB by 24°. If
exterior angle ㄥC is 108°. Find the angles of the ΔABC.
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A + 24 = B
C = 180- 108 = 72
A + B + C = 180
A + A + 24 + 72 = 180
2A = 180-96
A = 84°/2 = 42° , B = 42+ 24 = 66° , C = 72°
C = 180- 108 = 72
A + B + C = 180
A + A + 24 + 72 = 180
2A = 180-96
A = 84°/2 = 42° , B = 42+ 24 = 66° , C = 72°
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