In ABC, the measure of angle A is greater than the measure of angle B by 24°. If exterior angle C is 108°. Find the angles of the ABC.
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A-B =24
A+B=108
by elimination
2A=142
A=71
71+B=108
B=37
C+108=180
C=72
A+B=108
by elimination
2A=142
A=71
71+B=108
B=37
C+108=180
C=72
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