Question

in ∆ABC under what conditions tan²c/2tanb/2 + tan a/2tan²b/2+ tan²a/2tanb/2=tan²b/2tanc/2+ tan²c/2tana/2 + tan²a/2tanb/2

Answer 1

I don't understand your question

Answer 2



 

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if tanA/2,tanB/2,tanC/2 are in harmonic progression then find value of cotB/2

7 years ago

Answers : (3)

Dear student,

Use the concept:

tan (A + B + C) = 

= 

= 

So, since tan (A + B + C) = tan (1800) = 0 

So, tanA + tanB + tanC - tanA + tanB + tanC = 0

=> tanA + tanB + tanC = tanA + tanB + tanC.
(vi) cotA + cotB + cotA + cotC + cotB cotC = 1 
(vii)  
(viii)