Question

In ∆ABC, with median AD, BE and CF,
AB² + BC²+ AC² is equal to
a) AD²+BE²+CF²
b) 3/2AD²+BE²+CF²
c) 3/4AD²+BE²+CF²
d) 4/3AD²+BE²+CF²
Guys please help me in this question .... ​

Answer 1

Answer is given in the pic.