Question

in ∆ABD~∆ABC,AD:AC=5:10 ,If BC=15,then AB=????​

Answer 1

Answer:

Step-by-step explanation:

In right angles triangle BAC, AB=5cm and AC=12cm

Area of triangle=  

2

1

​

×base×height=  

2

1

​

×AB×AC

=  

2

1

​

×5×12=30cm  

2

 

Now, in ΔABC,

Area of triangle ABC=  

2

1

​

×BC×AD

⇒30=  

2

1

​

×13×AD

⇒ AD=  

13

30×2

​

=  

13

60

​

cm.

Answer 2

Ab^2=Ac^2+cB^2

Ab^2=100+255

Ab^2=325

Ab=18.25