Question

if A and B are two mutually exclusive events, then P(AUB) = P(A)+P(B).
a. true
b. false
c. P(AUB) = P(A/B)​

Answer 1

Step-by-step explanation:

Since A and B be mutually exclusive events in a sample space P(A∩B)=0

P(A)=0.3 P(B)=0.6

=0.3andP(B)=0.6

P(

A

_

∩

B

_

)= 1-P(AUB)

= 1- (P(A)+P(B)-P(A∩B))

=1- (0.3+0.6-0)

=0.1

If A and B are mutually exclusive events then P(A∩B) is always 0