IN ABOVE figure ,
AB is diameter show that angle ACB is a right angle .
Fill the blanks
AB is ______________ given
Arc AXB is __________
m(arc)=____________
measure of semi circle
m angle ACB= 1\2 × _______
=____________
m angle ACB is Right angle
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Answer:
AB is diameter
Arc AXB is 90°
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AB is 180° given. ( Reason:- It is Straight Line ).
Arc AXB is Minor Arc.
m(arc AXB) = 90° measure of semi circle.
m angle ACB= 1\2 × angle AOB.
Because,
Angle ACB = 90°
ACB = ½AOB
AOB = 45°
If,
Line AB = 180°
Semicircle = ½AB
So,
½ of 180° = 90°
- I Hope it's Helpful My Friend.
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