In above figure which bulb will get fuse ??
State the reason for your answer .
⭐A perfect answer required ! Thanks!
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Hey mate,
We can observe that the voltage remains constant in both the cases = 220V,
Bulb with lower power will have high resistance.
We will use formula R = V^2/P
When both bulbs are connected in series, the resistance will add up.
In series combination the bulb with higher resistance will handle more voltage,
So, 50 W will fuse first,
Calculations :-
R(50) = 220^2/50
= 968 ohms
R(100) = 220^2/100
= 484 ohms
Total R = 1452
We know,
V = I*R
So,
I = 440/1452
= 0.30 amp
Now V across 50W,
0.30*968 = 290.4 V
V across 100W,
0.30*484 = 145.2 V
You can see here that 50W will fuse due to high voltage.
But 100 W will glow with low intensity.
Hope this helps you out!
We can observe that the voltage remains constant in both the cases = 220V,
Bulb with lower power will have high resistance.
We will use formula R = V^2/P
When both bulbs are connected in series, the resistance will add up.
In series combination the bulb with higher resistance will handle more voltage,
So, 50 W will fuse first,
Calculations :-
R(50) = 220^2/50
= 968 ohms
R(100) = 220^2/100
= 484 ohms
Total R = 1452
We know,
V = I*R
So,
I = 440/1452
= 0.30 amp
Now V across 50W,
0.30*968 = 290.4 V
V across 100W,
0.30*484 = 145.2 V
You can see here that 50W will fuse due to high voltage.
But 100 W will glow with low intensity.
Hope this helps you out!
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