In ∆ABV,D,E are mod points of AB&AC such that DE=4.find BC.
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It's mid not mod and DE=4 what? Check ur question
NeetaSingh1:
∆ABC AND ∆ADE ARE SIMILAR ∆s. HENCE, RATIO OF SIDES IS 2:1 AS D IS MID POINT OF AB SO RATIO OF AB: AD=AC:AE = BC:DE =2:1 . SO BC = 8CM
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BC will be 8
according to mid point theorem
BC=2×DE=2×4=8
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according to mid point theorem
BC=2×DE=2×4=8
HOPE IT WILL HELP YOU
PLEASE MARK AS BRANLIEST
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