Question

in ACB=90°and cD|AB prove that BC2 \AC2=BD/AD

​

Answer 1

Question :

In the given figure   ∠ACB =90 CD ⊥ AB Prove that BC2/AC2 = BD/AD

Answer :

By AA similarity-criterion ∆ ACB ~ ∆CDB When two triangles are similar then the ratios of the lengths of their corresponding sides are proportional.By AA similarity-criterion ∆ ACB ~ ∆ADCWhen two triangles are similar then the ratios of their corresponding sides are proportional