in ACB=90°and cD|AB prove that BC2 \AC2=BD/AD
Answers
Answered by
4
Question :
In the given figure ∠ACB =90 CD ⊥ AB Prove that BC2/AC2 = BD/AD
Answer :
By AA similarity-criterion ∆ ACB ~ ∆CDB When two triangles are similar then the ratios of the lengths of their corresponding sides are proportional.By AA similarity-criterion ∆ ACB ~ ∆ADCWhen two triangles are similar then the ratios of their corresponding sides are proportional
Similar questions