Question

in acidic medium moles of KMnO4 required to oxidize 1.5 moles of Cu2S will be :

Answer 1

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..

Answer 2

Hey dear,

● Answer -
0.6 moles of KMnO4 are required to oxodize 1.5 moles of Cu2S.

● Explanation -
Oxidation of Cu2S by KMnO4 in acidic medium is given by -
Cu2S + 2KMnO4 + 4H2SO4 → 2CuSO4 + K2SO4 + 2MnSO4 + 4H2O

Valence factor of Mn => 5
Valence factor of Cu => 2

Moles of KMnO4 is calculated by -
n(KMnO4) = n(Cu2S) × valence factor of Cu / valence factor of Mn
n(KMnO4) = 1.5 × 2 / 5
n(KMnO4) = 0.6 moles


Therefore, 0.6 moles of KMnO4 are required.

Hope this helps you...