Question

in acidic medium the standard reduction potential of NO converted to n2o is 1.59 volt its Standard potential in alkaline medium at 298 Kelvin would be

Answer 1

Given in the equation :-

NO ------→ N₂O    [ E⁰ = 1.59]

Now the reaction for acidic medium  :-

2NO +2H⁺ -----→ N₂O + H₂O   
E⁰ =1.59

Reaction for basic medium :-

2NO + H₂O -----→ N₂O + 2OH⁻ 
Let E⁰ = x

Now the main reversible for alkaline medium 

H₂O ⇆ H⁺ + OH⁻
$K$ = 10⁻¹⁴ .

or balanced reaction

2H₂O ⇆ 2H⁺ + 2OH⁻
$K$ = 10⁻²⁸ .


Now, The formula for calculating cell potential

E⁰cell = (0.059 /n ) log K 
E⁰cell = (0.059/2) × log 10⁻²⁸
E⁰cell = (0.295) × (28)
E⁰cell = 0.826

Now for standard potential

$E^0 _{acidic} +E^0_{basic} = E^0_{cell}$
1.59 + x = 0.826
x = 0.764 

Hence 0.764 is the required potential.



Hope it Helps :-)