In adjoining figur DE//BC. Then find x
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Given :-
- DE || BC .
- AD = (2x - 1)
- DB = (x - 3)
- AE = (2x + 5)
- EC = (x - 1)
To Find :-
- value of x ?
Solution :-
since DE || BC .
so,
→ AD / DB = AE / EC (BPT)
putting values we get,
→ (2x - 1) / (x - 3) = (2x + 5) / (x - 1)
→ (2x - 1)(x - 1) = (x - 3)(2x + 5)
→ 2x² - 2x - x + 1 = 2x² + 5x - 6x - 15
→ 1 - 3x = - x - 15
→ -3x + x = -15 - 1
→ (-2x) = (-16)
→ x = 8 (Ans.)
Hence, value of x will be 8.
Learn more :-
In ABC, AD is angle bisector,
angle BAC = 111 and AB+BD=AC find the value of angle ACB=?
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