Question

In adjoining figure,if PQ is incident wavefront and RS is refracted wavefront (PR is interface of two mediums)then sin alpha/sin beta

Answer 1

Answer:

if PQ is incident wavefront and RS is refracted wavefront (PR is interface of two mediums)then sin alpha/sin beta is 3 : 2

Explanation:

Here we know that incident wavefront makes and angle "alpha" and its refracted wavefront makes and angle "beta"

so here angle of incidence of the light on the interface will be

$i = \alpha$

also we know that angle of refraction of light

$r = \beta$

so we will have

$\mu_1 sin i = \mu_2 sin r$

so we have

$1 sin \alpha = \frac{3}{2} sin\beta$

so we have

$\frac{sin \alpha}{sin \beta} = \frac{3}{2}$

#Learn

Topic : Snell's law

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