In adjoining figure in ∆ ABC, point D is on side AC. If AC= 15, DC=7 and BP⊥AC, then find A(∆ABD)/A(BDC).
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Answer:
Let ABC and PQR be two right triangles with AB ⊥ BC and PQ ⊥ QR.
Given:
BC = 9, AB = 5, PQ = 6 and QR = 10.
∴
A(△ABC)
A(△PQR)
=
AB×BC
PQ×QR
=
5×9
6×10
=
3
4
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