in agiven figure OACB is quadrant of acircle with centre O And radius 3.5 if OD=2cm find the area of shaded region
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firstly give the picture of the figure
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Area of equilateral triangle

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Radius of circle = 100 cm (half of a)
Area of circle = πr2 = π x 1002 = 31400 sq cm
Area of three sectors = ½ Area of circle (Because all angles sum up to 180)
= ½ x 31400 = 15700 sq cm
So, area of shaded portion = 17302.5 – 15700 = 1602.5 sq cm

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Radius of circle = 100 cm (half of a)
Area of circle = πr2 = π x 1002 = 31400 sq cm
Area of three sectors = ½ Area of circle (Because all angles sum up to 180)
= ½ x 31400 = 15700 sq cm
So, area of shaded portion = 17302.5 – 15700 = 1602.5 sq cm
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Given,OACB is a quadrant of a circle
Radius = 3.5 =7/2 cm; OD= 2cm
=1/4πr²-1/2×b×h
=1/4×22/7×7/2×7/2-1/2×7/2×2
=11×7/2×2×2 -7/2
[=77/8-7/2
=9.625-3.5
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