in alpha beta are the zeroes of the polynomial 2y2+7y+5,write the value of (alpha)+ ( beta)+(alpha)(beta)
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Given polynomial is (2y² + 7y + 5)
Since, α and β are the zeroes of the above polynomial
α + β = -7/2 ...(i)
and
αβ = 5/2 ...(ii)
Now,
α + β + αβ
= -7/2 + 5/2
= 1/2 ( - 7 + 5 )
= 1/2 ( - 2 )
= - 1
#MarkAsBrainliest
Given polynomial is (2y² + 7y + 5)
Since, α and β are the zeroes of the above polynomial
α + β = -7/2 ...(i)
and
αβ = 5/2 ...(ii)
Now,
α + β + αβ
= -7/2 + 5/2
= 1/2 ( - 7 + 5 )
= 1/2 ( - 2 )
= - 1
#MarkAsBrainliest
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