Question

In an A.C. circuit with phase voltage V and current I, the power dissipated is(a) VI(b) V²I(c) VI² (d) V²I²

Answer 1

In an A.C circuit with phase voltage V and current I, the power dissipated is VI which is the first option. Power is nothing but the energy consumed in unit time. It can also be defined as the product between voltage V and current I.

Answer 2

Explanation:

• If I is electric current and V is voltage, the power dissipated is given by :

$P=V\times I$

• Another formula of power dissipated is given by using Ohm's law. Since, V = IR. So,

$P=IR\times I\\\\P=I^2R$

Also, $I=\dfrac{V}{R}$

So,

$P=V\times \dfrac{V}{R}\\\\P= \dfrac{V^2}{R}$

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Electric power

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