Question

In an A.P. 17th term is 7 more than its 10th term. Find the common difference.
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Answer 1

a17=a10+7

a+16d=a+9d+7

16d-9d=7

7d=7

d=1

Answer 2

$\huge\underline\mathbb\color{gold}{Answer}$

$\red{a17 = a10 + 7}$

$\red{a + 16d = a + 9d + 7}$

$\red{16d - 9d = 7}$

$\red{7d = 7}$

$\red{d = 7/7}$

$\bold\red{d = 1}$