Question

In an A.P. 17th term is 7 more than its 10th term. Find the common difference. Solve the word problem

Answer 1

Hey

Here is your answer,

An = a + (n-1) d

A17 = 7+A10
a + (17-1) d = 7 + a + (10-1) d
a + 16d = 7 + a + 9d
16d = 7 + 9d
16d - 9d = 7
7d = 7
d = 7/7
d = 1

The common difference is 1.

Hope it helps you!

Answer 2

Answer:

let the first term of the AP be a and the common difference d

tn = a+ (n-1) d. ......(formula)

t17=a+(17-1)d. .......( substituting the values)

t17= a+16d .......(1)

t10=a+(10-1)d

t10=a+9d. ......(2)

from from the given condition and from (1) and +(2),

a+16d=a+9d+7. ....( because 7 is

more than 10th

term ) (given)

16d - 9d = 7

7d=7

d= 7/7

d = 1

therefore the common difference is 1

hope it will help you....

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