In an A.P 17th term is 7 more then its 10th term. find the common difference
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13
Sol:
Let a be the first term and d be the common difference of A.P.
17th term of A.P t17 = a + 16d.
10th term of A.P is t10 = a + 9d.
Given that 17th term of an A.P exceeds its 10th term by 7.
a + 16d = a + 9d + 7
7d = 7
∴ d = 1
prabhat56:
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Answered by
8
formula : An = a+ (n-1)d
A17 = a+16d ---- ©
A10 = a+9d -----©
from ©&© a+16d = a+9d+10. [as 17th term is 10 more than 10th term]
On solving : d = 1
A17 = a+16d ---- ©
A10 = a+9d -----©
from ©&© a+16d = a+9d+10. [as 17th term is 10 more than 10th term]
On solving : d = 1
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