In an A.P 8th term is 16 and 16th term is 48. ( a) find the common difference of the A.P (b)find the 25th term of the A.P
Answers
Step-by-step explanation:
We have, a
8
=31 and a
15
=16+a
11
⟹a+7d=31 and a+14d=16+a+10d
⟹a+7d=31 and 4d=16
⟹a+7d=31 and d=4⟹a+7×4=31
⟹a+28=31⟹a=3
Hence, the AP is a,a+d,a+2d,a+3d ...
i.e.,3, 7, 11, 15, 19, ...
Given : In an A.P 8th term is 16 and 16th term is 48.
To Find :
( a) find the common difference of the A.P
(b)find the 25th term of the A.P
Solution:
nth term = a + (n - 1) d
a = first term
d = common difference
8th term = 16
=> a + 7d = 16
16th term is 48
=> a + 15d = 48
=> 8d = 32
=> d = 4
the common difference of the A.P = 4
25th term of the A.P
= a + 24d
= a + 15d + 9d
= 48 + 9(4)
= 48 + 36
= 84
25th term of the A.P is 84
Learn More:
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In an A.P if sum of its first n terms is 3n square +5n and it's Kth term ...
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