In an A.P consisting of 27 terms, the sum of the first three terms is 21 and
that of the three middle terms is 93. Find the first term and the common
difference.
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- Total terms in AP = 27 terms
- Sum of 3 middle terms = 93
- Sum of 1st 3 terms = 21
- Common difference.
- Let the 1st three terms as = a , a+d , a+ 2d
→ a + a + d + a + 2d = 21
→ 3a + 3d = 21
→ a + d = 21/3
→ a + d = 7 .
→ d = 7-a
- Middle terms of AP = 13h , 14th and 15th
→ a + 12d + a+13d + a+14 d = 93
→ 3a + 39d = 93
→ 3 a + 39(7-a) = 93
→ 3a + 273 - 39a = 93
→ 273 -93 = 36a
→ 180 = 36a
→ a = 5
→ d = 7-5
- d = 2 .
Common difference is 2
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