In an A.P, first term=a, difference is d, last term is L, find the term before last
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Given: first term=a, difference is d, last term is L
To find: the term before last term in AP.
Solution:
- Now we have given that:
first term = a
common difference = d
last term = l
- Let the number of terms be n.
Then a(n) = l
- We know the formula:
a(n) = a + (n-1)d
- So we get:
a + (n-1)d = l
(n-1)d = l - a
n - 1 = (l - a) / d
n = (l - a) / d + 1
n = (l - a + d) / d
n-1 = (l - a + d) / d - 1
n - 1 = (l - a)/d
Answer:
So the second last term is (l - a)/d.
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Step-by-step explanation:
An=a+(n-1)d=L
The term before last is An-1
An-1=a+(n-1-1)d
=a+(n-2)d
=l-d
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