In an A.P. if the 12th term is -13 and the sum of its first four terms is 24. Find
the sum of its first 20 terms.
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Answer:
Step-by-step explanation:
T12=a+11d
-13 = a + 11d......................(1)
then S4 = 24
T1+T2+T3+T4 = 24
(a)+(a+d)+(a+2d)+(a+3d) = 24
4a+6d = 24
2a + 3d = 12....................(2)
solving 1 and 2
a= 9 and d = -2
and S20 = 10 x (2(18) + 19x-2)
= 10 x ( 36 -38)
= 10 (-2)
= -20
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