Question

. In an A.P. sum of three consecutive.
Terms is 33 and their sum of their squares.
IS 413. Find the Three numbers​

Answer 1

Answer:

A] Let three numbers be a - d, a, a + d

given

a - d + a + a + d = 21

3a = 21

∴a=7

(a + d) (a - d) a = 315

=(7+d)(7−d)×7=315

=(7

2

−d

2

)=45

=7

2

−45=d

2

=49−45=d

2

=4=d

2

d=±2

numbers are

7 - 2 , 7 , 7 + 2

= 5 , 7 , 9

Answer 2

Answer:

29 is the answer of the question