Question

In an A.P.sum ofthree consecutive terms is 21 and their productis 315, find the terms.
(Assume that three consecutive terms in A.P. are a-d, a, a + d.)
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Answer 1

Answer:

I don't know really this answer I am really sorry sorry sorry sorry ..I need points...

Answer 2

5, 7, 9

Step-by-step explanation:

Let three consecutive terms be:

(a-d), (a), (a+d)

then,

sum of terms = 21

a - d + a + a + d = 21

3a = 21

a = 7

and,

product of terms = 315

(a-d) (a) (a+d) = 315

a (a²-d²) = 315

7 (7² - d²) = 315

7² - d² = 45

49 - d² = 45

d² = 49 - 45

d = 2

so the three terms are:

(a - d) = 7 - 2 = 5

a = 7

(a + d) = 7 + 2 = 9

Hence the AP is:

5, 7, 9