In an A.P the first term is -5 and the last term is 45. if the sum of all numbers in the A.P is 120, then how many terms are there? what is the common difference?
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Here the number of terms for all nth terms of m AP series is =m
First term of the series ⇒ a=n
The common difference of the series
d=(2n−1)−n=n−1
So applying formula
S=2m(2n+(m−1)(n−1))
S=2m(2n+mn−m−n+1)
S=2m(mn−m+n+1)
Hence, this is the answer.
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