In an A.P, the sum of first ten terms is -80 and the sum of its next ten terms is -280.
Find the A.P
Answers
Answered by
4
Step-by-step explanation:
let the first term and d is the common differences of AP
= Sn=n/2{2a+(n-1)d}
now.............
=S10=10/2{2a+(10-1)d}
= -80=5(2a+9d)
= 2a+9d=-16.........(1)
again....
S20-S10=-280
=20/2{2a+19d}+80=-280
= 10{2a+19d}=-360
= 2a+19d=-36.........(2)
solve this two equation
then..
we found
d=-2
a=1
so...
AP=1,-1,-3,-5......
Answered by
2
hope it helps............
Attachments:
Similar questions