Question

In an A.P., the sum of the terms equidistant from the beginning and end is always same and equal to the sum of first term and the last term.

Answer 1

SOLUTION

Let a1, a2.....an an A.P., whose common difference is d.

Now, pth term from the beginning,

=) ap= a1+(p-1)d

pth term from the last

=)(n-p+1)the term from the beginning.

=) an-p+1

=) a1+(n-p+1-1)d

=) a1+ (n-p)d

Therefore,

(pth term from the beginning)+(pth term from the end)

=)[a1+(p-1)d]+[a1+(n-p)d]

=) 2a1+ (n-1)d

=) a1+ [a1+(n-1)d]

=) a1+ an

=) sum of first and last term.

hope it helps ☺️⬆️

Answer 2

i hope you like my answer .........